22⁶ ⋅ 2⁻⁸ 5) 44⁻³ ⋅ 11⁹;

5) $$\frac{22^6\cdot2^{-8}}{44^{-3}\cdot11^9} = \frac{(2\cdot11)^6\cdot2^{-8}}{(4\cdot11)^{-3}\cdot11^9} = \frac{2^6\cdot11^6\cdot2^{-8}}{(2^2\cdot11)^{-3}\cdot11^9} = \frac{2^{6-8}\cdot11^6}{2^{-6}\cdot11^{-3}\cdot11^9} = \frac{2^{-2}\cdot11^6}{2^{-6}\cdot11^6} = 2^{-2-(-6)} = 2^{-2+6} = 2^4 = 16$$.

Ответ: $$16$$