14) 1/4⁻¹⁰ ⋅ 1/49;

14) Упростим выражение:

$$ \frac{1}{4^{-10}} \cdot \frac{1}{49} = 4^{10} \cdot \frac{1}{7^2} = (2^2)^{10} \cdot \frac{1}{7^2} = 2^{20} \cdot \frac{1}{49} = \frac{2^{20}}{49} = \frac{1048576}{49} = 21400 \frac{16}{49} $$

$$ \frac{1}{4^{-10}} \cdot \frac{1}{49} = 4^{10} \cdot \frac{1}{7^2} = (2^2)^{10} \cdot \frac{1}{7^2} = 2^{20} \cdot \frac{1}{7^2} = \frac{2^{20}}{49} = \frac{1048576}{49} $$

$$ 1048576 \div 49 \approx 21400 $$

Ответ: 1048576/49