6) 10√3–4√48-√27

$$10\sqrt{3} - 4\sqrt{48} - \sqrt{27} = 10\sqrt{3} - 4\sqrt{16 \cdot 3} - \sqrt{9 \cdot 3} = 10\sqrt{3} - 4 \cdot 4\sqrt{3} - 3\sqrt{3} = 10\sqrt{3} - 16\sqrt{3} - 3\sqrt{3} = (10 - 16 - 3)\sqrt{3} = -9\sqrt{3}$$ Ответ: -9√3