① a) \(\frac{1}{3}+\frac{5}{8}\) б) \(\frac{7}{12}-\frac{3}{8}\) в) \(\frac{11}{15}-\frac{5}{12}\) г) \(\frac{3}{10}+\frac{8}{35}\) д) \(\frac{8}{15}-\frac{2}{9}\) e) \(\frac{4}{15}+\frac{4}{12}\) ж) \(\frac{11}{48}-\frac{5}{36}\) з) \(\frac{4}{5}-\frac{2}{3}+\frac{4}{15}\) и) \(\frac{7}{8}+\frac{11}{12}-\frac{5}{6}\)

a) \(\frac{1}{3}+\frac{5}{8}\) = \(\frac{1*8}{3*8} + \frac{5*3}{8*3}\) = \(\frac{8}{24} + \frac{15}{24}\) = \(\frac{8+15}{24}\) = \(\frac{23}{24}\)

Ответ: \(\frac{23}{24}\)

б) \(\frac{7}{12}-\frac{3}{8}\) = \(\frac{7*2}{12*2} - \frac{3*3}{8*3}\) = \(\frac{14}{24} - \(\frac{9}{24}\) = \(\frac{14-9}{24}\) = \(\frac{5}{24}\)

Ответ: \(\frac{5}{24}\)

в) \(\frac{11}{15}-\frac{5}{12}\) = \(\frac{11*4}{15*4} - \frac{5*5}{12*5}\) = \(\frac{44}{60} - \frac{25}{60}\) = \(\frac{44-25}{60}\) = \(\frac{19}{60}\)

Ответ: \(\frac{19}{60}\)

г) \(\frac{3}{10}+\frac{8}{35}\) = \(\frac{3*7}{10*7} + \frac{8*2}{35*2}\) = \(\frac{21}{70} + \frac{16}{70}\) = \(\frac{21+16}{70}\) = \(\frac{37}{70}\)

Ответ: \(\frac{37}{70}\)

д) \(\frac{8}{15}-\frac{2}{9}\) = \(\frac{8*3}{15*3} - \frac{2*5}{9*5}\) = \(\frac{24}{45} - \frac{10}{45}\) = \(\frac{24-10}{45}\) = \(\frac{14}{45}\)

Ответ: \(\frac{14}{45}\)

e) \(\frac{4}{15}+\frac{4}{12}\) = \(\frac{4*4}{15*4} + \frac{4*5}{12*5}\) = \(\frac{16}{60} + \frac{20}{60}\) = \(\frac{16+20}{60}\) = \(\frac{36}{60}\) = \(\frac{3*12}{5*12}\) = \(\frac{3}{5}\)

Ответ: \(\frac{3}{5}\)

ж) \(\frac{11}{48}-\frac{5}{36}\) = \(\frac{11*3}{48*3} - \frac{5*4}{36*4}\) = \(\frac{33}{144} - \frac{20}{144}\) = \(\frac{33-20}{144}\) = \(\frac{13}{144}\)

Ответ: \(\frac{13}{144}\)

з) \(\frac{4}{5}-\frac{2}{3}+\frac{4}{15}\) = \(\frac{4*3}{5*3} - \frac{2*5}{3*5} + \frac{4}{15}\) = \(\frac{12}{15} - \frac{10}{15} + \frac{4}{15}\) = \(\frac{12-10+4}{15}\) = \(\frac{6}{15}\) = \(\frac{2*3}{5*3}\) = \(\frac{2}{5}\)

Ответ: \(\frac{2}{5}\)

и) \(\frac{7}{8}+\frac{11}{12}-\frac{5}{6}\) = \(\frac{7*3}{8*3} + \frac{11*2}{12*2} - \frac{5*4}{6*4}\) = \(\frac{21}{24} + \frac{22}{24} - \frac{20}{24}\) = \(\frac{21+22-20}{24}\) = \(\frac{23}{24}\)

Ответ: \(\frac{23}{24}\)