③ a) \(7\frac{5}{6}-3\frac{2}{3}\) б) \(8\frac{5}{12}-6\frac{7}{20}\) в) \(11\frac{11}{12}-5\frac{7}{9}\) г) \(9\frac{17}{24}-8\frac{11}{36}\)

a) \(7\frac{5}{6}-3\frac{2}{3}\) = \((7-3) + (\frac{5}{6} - \frac{2}{3})\) = \(4 + (\frac{5}{6} - \frac{2*2}{3*2})\) = \(4 + (\frac{5}{6} - \frac{4}{6})\) = \(4 + \frac{1}{6}\) = \(4\frac{1}{6}\)

Ответ: \(4\frac{1}{6}\)

б) \(8\frac{5}{12}-6\frac{7}{20}\) = \((8-6) + (\frac{5}{12} - \frac{7}{20})\) = \(2 + (\frac{5*5}{12*5} - \frac{7*3}{20*3})\) = \(2 + (\frac{25}{60} - \frac{21}{60})\) = \(2 + \frac{4}{60}\) = \(2 + \frac{1}{15}\) = \(2\frac{1}{15}\)

Ответ: \(2\frac{1}{15}\)

в) \(11\frac{11}{12}-5\frac{7}{9}\) = \((11-5) + (\frac{11}{12} - \frac{7}{9})\) = \(6 + (\frac{11*3}{12*3} - \frac{7*4}{9*4})\) = \(6 + (\frac{33}{36} - \frac{28}{36})\) = \(6 + \frac{5}{36}\) = \(6\frac{5}{36}\)

Ответ: \(6\frac{5}{36}\)

г) \(9\frac{17}{24}-8\frac{11}{36}\) = \((9-8) + (\frac{17}{24} - \frac{11}{36})\) = \(1 + (\frac{17*3}{24*3} - \frac{11*2}{36*2})\) = \(1 + (\frac{51}{72} - \frac{22}{72})\) = \(1 + \frac{29}{72}\) = \(1\frac{29}{72}\)

Ответ: \(1\frac{29}{72}\)