a) \(3\frac{1}{18}-\frac{3}{8}\) = \(3 + \frac{1}{18} - \frac{3}{8}\) = \(3 + \frac{1*4}{18*4} - \frac{3*9}{8*9}\) = \(3 + \frac{4}{72} - \frac{27}{72}\) = \(3 - \frac{23}{72}\) = \(2 + \frac{72}{72} - \frac{23}{72}\) = \(2 + \frac{49}{72}\) = \(2\frac{49}{72}\)
Ответ: \(2\frac{49}{72}\)
б) \(7\frac{9}{20}-5\frac{17}{30}\) = \((7-5) + (\frac{9}{20} - \frac{17}{30})\) = \(2 + (\frac{9*3}{20*3} - \frac{17*2}{30*2})\) = \(2 + (\frac{27}{60} - \frac{34}{60})\) = \(2 - \frac{7}{60}\) = \(1 + \frac{60}{60} - \frac{7}{60}\) = \(1 + \frac{53}{60}\) = \(1\frac{53}{60}\)
Ответ: \(1\frac{53}{60}\)
в) \(4\frac{2}{7}-1\frac{4}{9}\) = \((4-1) + (\frac{2}{7} - \frac{4}{9})\) = \(3 + (\frac{2*9}{7*9} - \frac{4*7}{9*7})\) = \(3 + (\frac{18}{63} - \frac{28}{63})\) = \(3 - \frac{10}{63}\) = \(2 + \frac{63}{63} - \frac{10}{63}\) = \(2 + \frac{53}{63}\) = \(2\frac{53}{63}\)
Ответ: \(2\frac{53}{63}\)
г) \(8\frac{5}{36}-1\frac{43}{108}\) = \((8-1) + (\frac{5}{36} - \frac{43}{108})\) = \(7 + (\frac{5*3}{36*3} - \frac{43}{108})\) = \(7 + (\frac{15}{108} - \frac{43}{108})\) = \(7 - \frac{28}{108}\) = \(6 + \frac{108}{108} - \frac{28}{108}\) = \(6 + \frac{80}{108}\) = \(6\frac{80}{108}\) = \(6\frac{20}{27}\)
Ответ: \(6\frac{20}{27}\)
д) \(9\frac{7}{9}-4\frac{5}{6}\) = \((9-4) + (\frac{7}{9} - \frac{5}{6})\) = \(5 + (\frac{7*2}{9*2} - \frac{5*3}{6*3})\) = \(5 + (\frac{14}{18} - \frac{15}{18})\) = \(5 - \frac{1}{18}\) = \(4 + \frac{18}{18} - \frac{1}{18}\) = \(4 + \frac{17}{18}\) = \(4\frac{17}{18}\)
Ответ: \(4\frac{17}{18}\)
e) \(6\frac{7}{32}-2\frac{11}{48}\) = \((6-2) + (\frac{7}{32} - \frac{11}{48})\) = \(4 + (\frac{7*3}{32*3} - \frac{11*2}{48*2})\) = \(4 + (\frac{21}{96} - \frac{22}{96})\) = \(4 - \frac{1}{96}\) = \(3 + \frac{96}{96} - \frac{1}{96}\) = \(3 + \frac{95}{96}\) = \(3\frac{95}{96}\)
Ответ: \(3\frac{95}{96}\)