1) $$(3,6 - 2,5x) \cdot 1\frac{5}{7} - \frac{5}{7} = 1,6$$
$$(3,6 - 2,5x) \cdot \frac{12}{7} = 1,6 + \frac{5}{7}$$
$$(3,6 - 2,5x) \cdot \frac{12}{7} = \frac{16}{10} + \frac{5}{7}$$
$$(3,6 - 2,5x) \cdot \frac{12}{7} = \frac{8}{5} + \frac{5}{7}$$
$$(3,6 - 2,5x) \cdot \frac{12}{7} = \frac{56 + 25}{35}$$
$$(3,6 - 2,5x) \cdot \frac{12}{7} = \frac{81}{35}$$
$$3,6 - 2,5x = \frac{81}{35} : \frac{12}{7}$$
$$3,6 - 2,5x = \frac{81}{35} \cdot \frac{7}{12}$$
$$3,6 - 2,5x = \frac{81}{5 \cdot 12}$$
$$3,6 - 2,5x = \frac{27}{20}$$
$$3,6 - 2,5x = 1,35$$
$$-2,5x = 1,35 - 3,6$$
$$-2,5x = -2,25$$
$$x = \frac{-2,25}{-2,5}$$
$$x = 0,9$$
2) $$\frac{2}{3}y + 2y + \frac{5}{6}y + 1,5y = -0,35$$
Приведем все слагаемые к общему знаменателю 6:
$$\frac{4}{6}y + \frac{12}{6}y + \frac{5}{6}y + \frac{9}{6}y = -0,35$$
$$\frac{4+12+5+9}{6}y = -0,35$$
$$\frac{30}{6}y = -0,35$$
$$5y = -0,35$$
$$y = \frac{-0,35}{5}$$
$$y = -0,07$$