1. Берілген өрнектерді ықшамдаңдар: 1) 8/(6+x) − 8/(x−7); 2) (9a²+y²)/(3a−y) + 6ay/(y−3a); 3) ay/(a−yb) + (3a−by)/(by−a); 4) (a²x²+36y²)/(ax−6y) + 12axy/(6y−ax).

1. \(\dfrac{8}{x+6}-\dfrac{8}{x-7}=\dfrac{8(x-7)-8(x+6)}{(x+6)(x-7)}=\dfrac{-104}{(x+6)(x-7)}\).
   ОДЗ: \(x\ne-6,7\).
2. \(y-3a=-(3a-y)\), сондықтан
   \[\dfrac{9a^2+y^2}{3a-y}+\dfrac{6ay}{y-3a}=\dfrac{9a^2+y^2-6ay}{3a-y}=\dfrac{(3a-y)^2}{3a-y}=3a-y.\]
   ОДЗ: \(y\ne3a\).
3. \(by-a=-(a-by)\), сондықтан
   \[\dfrac{ay}{a-by}+\dfrac{3a-by}{by-a}=\dfrac{ay-(3a-by)}{a-by}=\dfrac{ay+by-3a}{a-by}.\]
   ОДЗ: \(a\ne by\).
4. \(6y-ax=-(ax-6y)\), сондықтан
   \[\dfrac{a^2x^2+36y^2-12axy}{ax-6y}=\dfrac{(ax-6y)^2}{ax-6y}=ax-6y.\]
   ОДЗ: \(ax\ne6y\).

Жауап: 1) \(-\dfrac{104}{(x+6)(x-7)}\); 2) \(3a-y\); 3) \(\dfrac{ay+by-3a}{a-by}\); 4) \(ax-6y\).