1) \(\frac{5}{6}-\frac{3}{8}+\left(\frac{5}{12}+\frac{1}{24}\right)\)

Приведём дроби к знаменателю 24:

\(\frac{5}{6}-\frac{3}{8}+\left(\frac{5}{12}+\frac{1}{24}\right)=\frac{20}{24}-\frac{9}{24}+\left(\frac{10}{24}+\frac{1}{24}\right)=\frac{20-9+10+1}{24}=\frac{22}{24}=\frac{11}{12}.\)

Ответ: \(\frac{11}{12}\).