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МатематикаВопрос:
1) In the triangle, two angles are 70° and 50°. Find the third angle.
Ответ:
Решение:
Сумма углов в любом треугольнике равна 180°. Чтобы найти третий угол, нужно из 180° вычесть сумму двух известных углов.
- Найдем сумму известных углов: 70° + 50° = 120°.
- Вычтем эту сумму из 180°: 180° - 120° = 60°.
Ответ: 60°
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- 4) In triangle ABC, angle C is 15°. Sides AC and BC are marked with equal dashes, indicating they are equal in length. Find the angle at vertex A.
- 5) In triangle ABC, sides AB and BC are equal. Angle ACD is 120°. Find the angles at A and B.
- 6) In triangle ABC, AB = BC. Angle CAD is marked with two arcs, and angle BAC is marked with one arc, suggesting they are equal. Angle C is 50°. Find the angle marked with a question mark.
- 7) In the figure ABCD, AB is parallel to CD, and AD is parallel to BC. The angle at vertex A is 137°, and the angle at vertex D is 0. This is likely a typo for a quadrilateral ABCD, where AB is parallel to CD and AD is parallel to BC, which makes it a parallelogram. In a parallelogram, opposite angles are equal and consecutive angles sum to 180°. If angle A is 137°, then angle C is also 137°. Angles B and D would be 180° - 137° = 43°. The notation '0' for angle D is incorrect. Assuming it's a parallelogram with ∠A = 137°.
