Ответ:
а) \(\frac{1}{5}+\frac{1}{3}=\frac{3}{15}+\frac{5}{15}=\frac{8}{15}\).
\(\frac{1}{6}+\frac{1}{2}=\frac{1}{6}+\frac{3}{6}=\frac{4}{6}=\frac{2}{3}=\frac{10}{15}\).
Так как \(\frac{8}{15}<\frac{10}{15}\), то \(\frac{1}{5}+\frac{1}{3}<\frac{1}{6}+\frac{1}{2}\).
б) \(-\frac{2}{17}-\frac{1}{3}=-\frac{6}{51}-\frac{17}{51}=-\frac{23}{51}\).
\(-\frac{1}{17}-\frac{2}{3}=-\frac{3}{51}-\frac{34}{51}=-\frac{37}{51}\).
Так как \(-\frac{23}{51}>-\frac{37}{51}\), то \(-\frac{2}{17}-\frac{1}{3}>-\frac{1}{17}-\frac{2}{3}\).
Ответ: а) \(<\); б) \(>\).
