\(\frac{3^6 \cdot (3^5)^2}{27^3} = \frac{3^6 \cdot 3^{10}}{(3^3)^3} = \frac{3^{6+10}}{3^{3\cdot 3}} = \frac{3^{16}}{3^9} = 3^{16-9} = 3^7\)
\(3^7 = 2187\)
Ответ: 2187