Решение:
- а) 1\(\frac{2}{3}\) + 3\(\frac{1}{3}\)
\( 1 + 3 + \frac{2}{3} + \frac{1}{3} = 4 + \frac{3}{3} = 4 + 1 = 5 \) - б) 2\(\frac{1}{6}\) + 3\(\frac{5}{6}\) + 4\(\frac{5}{6}\)
\( 2 + 3 + 4 + \frac{1}{6} + \frac{5}{6} + \frac{5}{6} = 9 + \frac{1+5+5}{6} = 9 + \frac{11}{6} = 9 + 1\(\frac{5}{6}\) = 10\(\frac{5}{6}\) \) - в) 7\(\frac{5}{12}\) - 1\(\frac{3}{24}\)
Приведём дроби к общему знаменателю 24: \( 7\(\frac{10}{24}\) - 1\(\frac{3}{24}\) = \( 6\(\frac{10-3}{24}\) = 6\(\frac{7}{24}\) \) - г) 9\(\frac{7}{18}\) - 6\(\frac{2}{36}\) + 11\(\frac{2}{9}\)
Приведём дроби к общему знаменателю 36: \( 9\(\frac{14}{36}\) - 6\(\frac{2}{36}\) + 11\(\frac{8}{36}\) = \( (9 - 6 + 11) + \frac{14 - 2 + 8}{36} = 14 + \frac{20}{36} = 14\(\frac{20}{36}\) = 14\(\frac{5}{9}\) \)
Ответ: а) 5; б) 10\(\frac{5}{6}\); в) 6\(\frac{7}{24}\); г) 14\(\frac{5}{9}\).