10)(4-3)(2)

$$ \left( 4\frac{1}{3} - 3\frac{4}{9} \right)^2 \cdot \left( 2\frac{1}{4} \right)^2 = \left( \frac{4 \cdot 3 + 1}{3} - \frac{3 \cdot 9 + 4}{9} \right)^2 \cdot \left( \frac{2 \cdot 4 + 1}{4} \right)^2 = \left( \frac{13}{3} - \frac{31}{9} \right)^2 \cdot \left( \frac{9}{4} \right)^2 = \left( \frac{13 \cdot 3}{3 \cdot 3} - \frac{31}{9} \right)^2 \cdot \frac{81}{16} = \left( \frac{39}{9} - \frac{31}{9} \right)^2 \cdot \frac{81}{16} = \left( \frac{8}{9} \right)^2 \cdot \frac{81}{16} = \frac{8^2}{9^2} \cdot \frac{81}{16} = \frac{64}{81} \cdot \frac{81}{16} = \frac{64}{16} = 4$$

Ответ: 4