11. Сократить дробь: 1) 12a²b³c⁵/(27a⁴b³c²); 2) a⁷(a−b)²/[a⁴(a−b)³]; 3) (2a+6)/(a²−9); 4) (m−2n)²/(10n−5m); 5) (a²−4)/(a³+8); 6) (8a³−27)/(9−4a²).

Question

Вопрос:

Accepted Answer

\(\frac{12a^2b^3c^5}{27a^4b^3c^2}=\frac{4c^3}{9a^2}\).
\(\frac{a^7(a-b)^2}{a^4(a-b)^3}=\frac{a^3}{a-b}\).
\(\frac{2a+6}{a^2-9}=\frac{2(a+3)}{(a-3)(a+3)}=\frac{2}{a-3}\).
\(\frac{(m-2n)^2}{10n-5m}=\frac{(2n-m)^2}{5(2n-m)}=\frac{2n-m}{5}\).
\(\frac{a^2-4}{a^3+8}=\frac{(a-2)(a+2)}{(a+2)(a^2-2a+4)}=\frac{a-2}{a^2-2a+4}\).
\(\frac{8a^3-27}{9-4a^2}=-\frac{4a^2+6a+9}{2a+3}\).

Ответ: