Ответ:

Grafikni chizish uchun quyidagi nuqtalarni hisoblaymiz: \(x=-2,-1,0,1,2\) da \(y=3x^2\) mos ravishda \(12,3,0,3,12\) bo‘ladi. Nuqtalarni silliq parabola bilan tutashtiramiz.

1) \(y=3x^2\) ga qiymatlarni qo‘yamiz:

  • \(x=-2.8\): \(y=3\cdot(-2.8)^2=23.52\);
  • \(x=-1.2\): \(y=3\cdot(-1.2)^2=4.32\);
  • \(x=1.5\): \(y=3\cdot1.5^2=6.75\);
  • \(x=2.5\): \(y=3\cdot2.5^2=18.75\).

2) \(y=3x^2\) dan \(x=\pm\sqrt{y/3}\). Har bir musbat \(y\) qiymatiga ikkita qarama-qarshi \(x\) mos keladi:

  • \(y=9\): \(x\approx\pm1.73\);
  • \(y=6\): \(x\approx\pm1.41\);
  • \(y=2\): \(x\approx\pm0.82\);
  • \(y=8\): \(x\approx\pm1.63\);
  • \(y=1.3\): \(x\approx\pm0.66\).