2) $$2\frac{1}{4} \cdot 2\frac{2}{27} + \left(3\frac{1}{6} + 4\frac{5}{11}\right) = \frac{9}{4} \cdot \frac{56}{27} + \left(\frac{19}{6} + \frac{49}{11}\right) = \frac{9 \cdot 56}{4 \cdot 27} + \left(\frac{19 \cdot 11}{6 \cdot 11} + \frac{49 \cdot 6}{11 \cdot 6}\right) = \frac{504}{108} + \frac{209 + 294}{66} = \frac{14}{3} + \frac{503}{66} = \frac{14 \cdot 22}{3 \cdot 22} + \frac{503}{66} = \frac{308 + 503}{66} = \frac{811}{66} = 12\frac{19}{66}$$
Ответ: $$12\frac{19}{66}$$