Ответ:

а) \(\left(\frac{4}{9}+\frac{5}{12}\right)\cdot\frac{18}{31}=\frac{31}{36}\cdot\frac{18}{31}=\frac{1}{2}\).

б) \(\frac{6}{25}\left(\frac{11}{15}-\frac{9}{20}\right)=\frac{6}{25}\cdot\frac{17}{60}=\frac{17}{250}\).

в) \((4-3\frac{7}{15})\cdot\frac{5}{8}=\frac{8}{15}\cdot\frac{5}{8}=\frac{1}{3}\).

г) \((5-4\frac{4}{7})(7\frac{1}{6}-6\frac{5}{12})=\frac{3}{7}\cdot\frac{2}{3}=\frac{2}{7}\).

д) \((1\frac{1}{24}-\frac{5}{12})(4\frac{1}{8}-3\frac{5}{24})=\frac{5}{8}\cdot\frac{11}{12}=\frac{55}{96}\).

е) \((1\frac{2}{15}-\frac{11}{15})(5\frac{3}{18}-4\frac{1}{27})=\frac{2}{5}\cdot\frac{61}{54}=\frac{61}{135}\).

Ответ: а) 1/2; б) 17/250; в) 1/3; г) 2/7; д) 55/96; е) 61/135.