Ответ:
а) \(\frac{7}{16}\cdot\frac{4}{9}-\frac{2}{15}=\frac{7}{36}-\frac{2}{15}=\frac{35-24}{180}=\frac{11}{180}\).
б) \(\frac{8}{15}\cdot(2\frac{1}{2})^2-\frac{5}{9}=\frac{8}{15}\cdot\frac{25}{4}-\frac{5}{9}=\frac{10}{3}-\frac{5}{9}=\frac{25}{9}=2\frac{7}{9}\).
в) \(((1\frac{1}{6})^2-\frac{7}{18})\cdot2\frac{4}{7}-1\frac{2}{5}=(\frac{49}{36}-\frac{14}{36})\cdot\frac{18}{7}-\frac{7}{5}=\frac{5}{2}-\frac{7}{5}=\frac{11}{10}=1\frac{1}{10}\).
г) \((\frac{11}{16}+\frac{7}{24}-\frac{5}{12})+(\frac{3}{4})^2=\frac{9}{16}+\frac{9}{16}=\frac{9}{8}=1\frac{1}{8}\).
Ответ: а) 11/180; б) 2 7/9; в) 1 1/10; г) 1 1/8.
