2.339. Вычислите: а) (1 1/5)²; б) (3/4 − 2/3)²; в) (1/3)³ − (1/9)².

1. а) \(1\frac{1}{5}=\frac{6}{5}\), поэтому \(\left(\frac{6}{5}\right)^2=\frac{36}{25}=1\frac{11}{25}\).
2. б) \(\left(\frac{3}{4}-\frac{2}{3}\right)^2=\left(\frac{9}{12}-\frac{8}{12}\right)^2=\left(\frac{1}{12}\right)^2=\frac{1}{144}\).
3. в) \(\left(\frac{1}{3}\right)^3-\left(\frac{1}{9}\right)^2=\frac{1}{27}-\frac{1}{81}=\frac{3}{81}-\frac{1}{81}=\frac{2}{81}\).

Ответ: а) \(1\frac{11}{25}\); б) \(\frac{1}{144}\); в) \(\frac{2}{81}\).