2) а) √(8m) − 0,2√(200m) + 3√(72m); б) 3√(12b) + 0,5√(108k) − 2√(48b) + 0,01√(300k)

а) \(\sqrt{8m}=2\sqrt{2m}\), \(\sqrt{200m}=10\sqrt{2m}\), \(\sqrt{72m}=6\sqrt{2m}\).

\(2\sqrt{2m}-0.2\cdot10\sqrt{2m}+3\cdot6\sqrt{2m}=(2-2+18)\sqrt{2m}=18\sqrt{2m}\).

б) \(\sqrt{12b}=2\sqrt{3b}\), \(\sqrt{48b}=4\sqrt{3b}\), \(\sqrt{108k}=6\sqrt{3k}\), \(\sqrt{300k}=10\sqrt{3k}\).

\(3\cdot2\sqrt{3b}+0.5\cdot6\sqrt{3k}-2\cdot4\sqrt{3b}+0.01\cdot10\sqrt{3k}\)

\(=6\sqrt{3b}+3\sqrt{3k}-8\sqrt{3b}+0.1\sqrt{3k}=-2\sqrt{3b}+3.1\sqrt{3k}\).

Ответ: а) \(18\sqrt{2m}\); б) \(-2\sqrt{3b}+3.1\sqrt{3k}\).