2) \(\left|\left(4\frac57-1\frac{11}{14}\right)\cdot4\frac23+\left(3\frac29-1\frac56\right)\cdot\frac{18}{25}\right|:2\frac34\)

Question

Вопрос:

Accepted Answer

\(4\frac57-1\frac{11}{14}=\frac{33}{7}-\frac{25}{14}=\frac{41}{14}\).

\(\frac{41}{14}\cdot4\frac23=\frac{41}{14}\cdot\frac{14}{3}=\frac{41}{3}\).

\(3\frac29-1\frac56=\frac{29}{9}-\frac{11}{6}=\frac{25}{18}\).

\(\frac{25}{18}\cdot\frac{18}{25}=1\).

\(\left|\frac{41}{3}+1\right|=\frac{44}{3}\).

\(\frac{44}{3}:2\frac34=\frac{44}{3}:\frac{11}{4}=\frac{44}{3}\cdot\frac{4}{11}=\frac{16}{3}\).

Ответ: \(\frac{16}{3}\).