3) $1\frac{9}{40}\cdot\left[7\frac57:3\frac35-\left(\frac{53}{56}-\frac{29}{35}\right):\frac{33}{40}\right]$

Question

Вопрос: $Фото задания: 3) $1\frac{9}{40}\cdot\left[7\frac57:3\frac35-\left(\frac{53}{56}-\frac{29}{35}\right):\frac{33}{40}\right]$$ Фото задания

Accepted Answer

$1\frac{9}{40}=\frac{49}{40}$, $7\frac57:3\frac35=\frac{54}{7}:\frac{18}{5}=\frac{15}{7}$.

$\frac{53}{56}-\frac{29}{35}=\frac{33}{280}$.

$\frac{33}{280}:\frac{33}{40}=\frac17$.

Содержимое скобок: $\frac{15}{7}-\frac17=2$.

$\frac{49}{40}\cdot2=\frac{49}{20}=2\frac{9}{20}$.

Ответ: $\frac{49}{20}=2\frac{9}{20}$.

3) \(1\frac{9}{40}\cdot\left[7\frac57:3\frac35-\left(\frac{53}{56}-\frac{29}{35}\right):\frac{33}{40}\right]\)