2) Найти значение выражения:
- a) \( f(x) = \frac{3}{5-4x} \)
\( f'(x) = \frac{-3(-4)}{(5-4x)^2} = \frac{12}{(5-4x)^2} \)
\( f'(1.5) = \frac{12}{(5 - 4 × 1.5)^2} = \frac{12}{(5 - 6)^2} = \frac{12}{(-1)^2} = 12 \) - б) \( f(x) = 3\sin x \)
\( f'(x) = 3\cos x \)
\( f'(-\frac{\pi}{4}) = 3\cos(-\frac{\pi}{4}) = 3 \cdot \frac{\sqrt{2}}{2} = \frac{3\sqrt{2}}{2} \)
Ответ: a) 12; б) \(\frac{3\sqrt{2}}{2}\).