2. Сократите: а) (9·14)/(28·3); б) (44·36)/(27·55); в) (3·5+7·5)/25.

1. \(\dfrac{9\cdot14}{28\cdot3}=\dfrac{3\cdot14}{28}=\dfrac{3}{2}\).
2. \(\dfrac{44\cdot36}{27\cdot55}=\dfrac{4\cdot36}{27\cdot5}=\dfrac{4\cdot4}{3\cdot5}=\dfrac{16}{15}\).
3. \(\dfrac{3\cdot5+7\cdot5}{25}=\dfrac{15+35}{25}=\dfrac{50}{25}=2\).

Ответ: а) \(\dfrac{3}{2}\); б) \(\dfrac{16}{15}\); в) \(2\).