2. Вычислить \(\dfrac{\sqrt{2^4\cdot5^2\cdot3}}{\sqrt{48}}\).

\[\frac{\sqrt{2^4\cdot5^2\cdot3}}{\sqrt{48}}=\sqrt{\frac{2^4\cdot5^2\cdot3}{48}}=\sqrt{\frac{16\cdot25\cdot3}{16\cdot3}}=\sqrt{25}=5.\]

Ответ: 5.