а)
\[ 3\frac{1}{5} = \frac{3 \times 5 + 1}{5} = \frac{16}{5} \]
\[ 3\frac{1}{8} = \frac{3 \times 8 + 1}{8} = \frac{25}{8} \]
\[ \frac{16}{5} \cdot \frac{25}{8} = \frac{16 \times 25}{5 \times 8} \]
\[ \frac{2}{1} \cdot \frac{5}{1} = 10 \]
б)
\[ 1\frac{4}{11} = \frac{1 \times 11 + 4}{11} = \frac{15}{11} \]
\[ 1\frac{2}{13} = \frac{1 \times 13 + 2}{13} = \frac{15}{13} \]
\[ \frac{15}{11} : \frac{15}{13} = \frac{15}{11} \cdot \frac{13}{15} \]
\[ \frac{1}{11} \cdot \frac{13}{1} = \frac{13}{11} \]
\[ \frac{13}{11} = 1\frac{2}{11} \]
в)
\[ 2\frac{3}{4} = \frac{2 \times 4 + 3}{4} = \frac{11}{4} \]
\[ 1\frac{3}{8} = \frac{1 \times 8 + 3}{8} = \frac{11}{8} \]
\[ 3\frac{3}{7} = \frac{3 \times 7 + 3}{7} = \frac{24}{7} \]
\[ \frac{11}{4} : \frac{11}{8} = \frac{11}{4} \cdot \frac{8}{11} \]
\[ \frac{1}{1} \cdot \frac{2}{1} = 2 \]
\[ 2 \cdot \frac{24}{7} = \frac{2}{1} \cdot \frac{24}{7} = \frac{48}{7} \]
\[ \frac{48}{7} = 6\frac{6}{7} \]
Ответ: а) 10; б) \(1\frac{2}{11}\); в) \(6\frac{6}{7}\).