Ответ:
2. Выполнение действий:
- а) \(\begin{aligned}\)\(\frac{2x}{x-a}\) - \(\frac{2a}{x+a}\) &= \(\frac{2x(x+a) - 2a(x-a)}{(x-a)(x+a)}\) \\ &= \(\frac{2x^2 + 2ax - 2ax + 2a^2}{x^2-a^2}\) \\ &= \(\frac{2x^2+2a^2}{x^2-a^2}\)\(\end{aligned}\)
- б) \(\begin{aligned}\)\(\frac{2-ab}{2a+ab}\) + \(\frac{2b}{2+b}\) &= \(\frac{2-ab}{a(2+b)}\) + \(\frac{2b}{2+b}\) \\ &= \(\frac{2-ab + 2ba}{a(2+b)}\) \\ &= \(\frac{2+ab}{a(2+b)}\)\(\end{aligned}\)
- в) \(\begin{aligned}\)c - \(\frac{c^2}{c+1}\) &= \(\frac{c(c+1) - c^2}{c+1}\) \\ &= \(\frac{c^2+c - c^2}{c+1}\) \\ &= \(\frac{c}{c+1}\)\(\end{aligned}\)
Ответ: а) \(\frac{2x^2+2a^2}{x^2-a^2}\); б) \(\frac{2+ab}{a(2+b)}\); в) \(\frac{c}{c+1}\).
