Решение:
- \( 3\frac{1}{4} = \frac{3\cdot4+1}{4} = \frac{13}{4} \)
- \( 4\frac{2}{8} = \frac{4\cdot8+2}{8} = \frac{34}{8} \)
- \( 8\frac{1}{2} = \frac{8\cdot2+1}{2} = \frac{17}{2} \)
- \( 5\frac{3}{7} = \frac{5\cdot7+3}{7} = \frac{38}{7} \)
- \( 6\frac{4}{11} = \frac{6\cdot11+4}{11} = \frac{70}{11} \)
- \( 7\frac{3}{8} = \frac{7\cdot8+3}{8} = \frac{59}{8} \)
- \( 9\frac{5}{6} = \frac{9\cdot6+5}{6} = \frac{59}{6} \)
- \( 12\frac{1}{3} = \frac{12\cdot3+1}{3} = \frac{37}{3} \)
- \( 2\frac{4}{15} = \frac{2\cdot15+4}{15} = \frac{34}{15} \)
Ответ: 1) \( \frac{13}{4} \), 2) \( \frac{34}{8} \), 3) \( \frac{17}{2} \), 4) \( \frac{38}{7} \), 5) \( \frac{70}{11} \), 6) \( \frac{59}{8} \), 7) \( \frac{59}{6} \), 8) \( \frac{37}{3} \), 9) \( \frac{34}{15} \).