26. Решите уравнение: a) \( \frac{8}{25} x = 3 \frac{1}{5} \) б) \( 3 \frac{1}{12} - 1 \frac{5}{6} y = 1 \frac{17}{24} \) в) \( (\frac{7}{12} + \frac{11}{30}) x : 7 \frac{1}{4} = 1 \frac{1}{3} \)

Решение:

а)
\( \frac{8}{25} x = 3 \frac{1}{5} \)
\( \frac{8}{25} x = \frac{16}{5} \)
\( x = \frac{16}{5} : \frac{8}{25} \)
\( x = \frac{16}{5} \cdot \frac{25}{8} \)
\( x = \frac{16 \cdot 25}{5 \cdot 8} = \frac{2 \cdot 5}{1} = 10 \)

б)
\( 3 \frac{1}{12} - 1 \frac{5}{6} y = 1 \frac{17}{24} \)
\( \frac{37}{12} - \frac{11}{6} y = \frac{41}{24} \)
\( \frac{11}{6} y = \frac{37}{12} - \frac{41}{24} \)
\( \frac{11}{6} y = \frac{74}{24} - \frac{41}{24} \)
\( \frac{11}{6} y = \frac{33}{24} \)
\( y = \frac{33}{24} : \frac{11}{6} \)
\( y = \frac{33}{24} \cdot \frac{6}{11} \)
\( y = \frac{33 \cdot 6}{24 \cdot 11} = \frac{3 \cdot 1}{4 \cdot 1} = \frac{3}{4} \)

в)