\(\left(1\frac{1}{3}\right)^2 \cdot \left(3\frac{1}{16} + 0,75\right) = \left(\frac{4}{3}\right)^2 \cdot \left(\frac{49}{16} + \frac{3}{4}\right) = \frac{16}{9} \cdot \left(\frac{49}{16} + \frac{12}{16}\right) = \frac{16}{9} \cdot \frac{61}{16} = \frac{61}{9} = 6\frac{7}{9}