Выражение: \( -3\frac{1}{9} : 2\frac{1}{3} \cdot \left(-\frac{9}{16}\right) \).
\( -3\frac{1}{9} = -\frac{3 \cdot 9 + 1}{9} = -\frac{27+1}{9} = -\frac{28}{9} \)
\( 2\frac{1}{3} = \frac{2 \cdot 3 + 1}{3} = \frac{6+1}{3} = \frac{7}{3} \)
\( -\frac{28}{9} : \frac{7}{3} \cdot \left(-\frac{9}{16}\right) \)
\( -\frac{28}{9} \cdot \frac{3}{7} \cdot \left(-\frac{9}{16}\right) \)
\( \frac{28}{9} \cdot \frac{3}{7} \cdot \frac{9}{16} \)
\( \frac{\cancel{28}^4}{\cancel{9}^1} \cdot \frac{\cancel{3}^1}{\cancel{7}^1} \cdot \frac{\cancel{9}^1}{\cancel{16}^4} = \frac{4}{1} \cdot \frac{1}{1} \cdot \frac{1}{4} = \frac{4}{4} = 1 \)
Ответ: 1