Дано уравнение: \( \frac{2x-3}{10} = \frac{x+4}{15} - 2 \).
\[ 30 \cdot \frac{2x-3}{10} = 30 \cdot \left( \frac{x+4}{15} - 2 \right) \]
\[ 3(2x-3) = 2(x+4) - 30 \cdot 2 \]
\[ 6x - 9 = 2x + 8 - 60 \]\[ 6x - 9 = 2x - 52 \]\[ 6x - 2x = -52 + 9 \]\[ 4x = -43 \]\[ x = \frac{-43}{4} \]\[ x = -10.75 \]Ответ: \( x = -10.75 \).