Решим уравнение \( \frac{1}{3}x - 1 = \frac{1}{4}(x + \frac{4}{5}) \).
\( \frac{1}{3}x - 1 = \frac{1}{4}x + \frac{1}{4} \cdot \frac{4}{5} \)
\( \frac{1}{3}x - 1 = \frac{1}{4}x + \frac{1}{5} \)
\( 60 \cdot (\frac{1}{3}x - 1) = 60 \cdot (\frac{1}{4}x + \frac{1}{5}) \)
\( 60 \cdot \frac{1}{3}x - 60 \cdot 1 = 60 \cdot \frac{1}{4}x + 60 \cdot \frac{1}{5} \)
\( 20x - 60 = 15x + 12 \)
\( 20x - 15x = 12 + 60 \)
\( 5x = 72 \)
\( x = \frac{72}{5} \)
\( x = 14.4 \)
Ответ: \( x = \frac{72}{5} \) или \( x = 14.4 \).