\(\sqrt[3]{\frac{\sqrt{3}}{\sqrt{96}}} = \sqrt[3]{\sqrt{\frac{3}{96}}} = \sqrt[6]{\frac{3}{96}} = \sqrt[6]{\frac{1}{32}} = \sqrt[6]{\frac{1}{2^5}} = \frac{1}{\sqrt[6]{32}} = \frac{1}{\sqrt[6]{2^5}} = 2^{-\frac{5}{6}}\)
Ответ: \( 2^{-\frac{5}{6}} \) или \(\frac{1}{\sqrt[6]{32}}\).