Ответ:
\(\frac{14a\cdot b^{-2}}{b^{-4}\cdot64a^4}=\frac{14}{64}\,a^{1-4}b^{-2-(-4)}=\frac{7}{32}a^{-3}b^2=\frac{7b^2}{32a^3}\).
\(\frac{18x^{-6}\cdot7y^{-5}}{y^5\cdot12x^{-12}}=\frac{126}{12}x^{-6-(-12)}y^{-5-5}=\frac{21}{2}x^6y^{-10}=\frac{21x^6}{2y^{10}}\).
