Приведём дроби к общему знаменателю \( (a-3)^2(a+3) \).
\(\frac{2}{a-3} - \frac{a}{(a-3)^2} - \frac{a^2}{(a-3)(a+3)} = \frac{2(a-3)(a+3)}{(a-3)^2(a+3)} - \frac{a(a+3)}{(a-3)^2(a+3)} - \frac{a^2(a-3)}{(a-3)^2(a+3)}\)
\(= \frac{2(a^2-9) - (a^2+3a) - (a^3-3a^2)}{(a-3)^2(a+3)} = \frac{2a^2-18 - a^2-3a - a^3+3a^2}{(a-3)^2(a+3)}\)
\(= \frac{-a^3 + 4a^2 - 3a - 18}{(a-3)^2(a+3)}\)
Ответ: \(\frac{-a^3 + 4a^2 - 3a - 18}{(a-3)^2(a+3)}\).