Вопрос:

3. Вычислите: 1) \((0.008+0.992):(5\cdot0.6-1.4)\); 2) \(13.5\cdot9.1\cdot(-3.3):(-0.00013)\); 3) \((8\frac{7}{12}-2\frac{17}{36})\cdot2.7-4\frac13:0.65\); 4) \((1\frac{11}{24}+\frac{13}{36})\cdot1.44-\frac{8}{15}\cdot0.5625\).

Ответ:

  1. \((0.008+0.992):(5\cdot0.6-1.4)=1:1.6=0.625\).
  2. \(13.5\cdot9.1\cdot(-3.3):(-0.00013)=3308850\).
  3. \(\left(8\frac7{12}-2\frac{17}{36}\right)\cdot2.7-4\frac13:0.65=\frac{265}{36}\cdot\frac{27}{10}-\frac{13}{3}:\frac{13}{20}=\frac{159}{8}-\frac{20}{3}=\frac{317}{24}=13\frac5{24}\).
  4. \(\left(1\frac{11}{24}+\frac{13}{36}\right)\cdot1.44-\frac8{15}\cdot0.5625=\frac{151}{72}\cdot\frac{36}{25}-\frac8{15}\cdot\frac9{16}=\frac{151}{50}-\frac3{10}=\frac{68}{25}=2.72\).