Ответ:

  1. \(1\dfrac{7}{18}-\dfrac{4}{15}=1+\dfrac{35}{90}-\dfrac{24}{90}=1\dfrac{11}{90}\).
  2. \(4\dfrac{4}{5}\cdot4\dfrac{1}{6}=\dfrac{24}{5}\cdot\dfrac{25}{6}=20\).
  3. \(3\dfrac{1}{9}:4\dfrac{2}{3}=\dfrac{28}{9}:\dfrac{14}{3}=\dfrac{28}{9}\cdot\dfrac{3}{14}=\dfrac{2}{3}\).
  4. \((30:27-\dfrac{1}{3})\cdot2\dfrac{1}{7}+\dfrac{2}{5}=\left(\dfrac{10}{9}-\dfrac{1}{3}\right)\cdot\dfrac{15}{7}+\dfrac{2}{5}=\dfrac{7}{9}\cdot\dfrac{15}{7}+\dfrac{2}{5}=\dfrac{5}{3}+\dfrac{2}{5}=\dfrac{31}{15}=2\dfrac{1}{15}\).

Ответ: 1) \(1\dfrac{11}{90}\); 2) \(20\); 3) \(\dfrac{2}{3}\); 4) \(2\dfrac{1}{15}\).