Ответ:\(\sqrt[5]{3^{10}\cdot2^{15}}=3^2\cdot2^3=9\cdot8=72.\)\(\sqrt[3]{2^3\cdot5^6}=2\cdot5^2=50.\)\(\sqrt[4]{3^{12}(\frac13)^8}=\sqrt[4]{3^4}=3.\)\(\sqrt[10]{4^{30}(\frac12)^{20}}=\sqrt[10]{2^{60-20}}=\sqrt[10]{2^{40}}=2^4=16.\)