4) \(-3\frac{1}{3} \cdot 1,9 + 19,5 : 4\frac{1}{3}\) : \(0,16 - \frac{62}{75}\);

Решение:

1. \( -3\frac{1}{3} \cdot 1,9 = -\frac{10}{3} \cdot \frac{19}{10} = -\frac{19}{3} \)
2. \( 19,5 : 4\frac{1}{3} = \frac{39}{2} : \frac{13}{3} = \frac{39}{2} \cdot \frac{3}{13} = \frac{3 \cdot 3}{2} = \frac{9}{2} = 4,5 \)
3. \( -\frac{19}{3} + 4,5 = -\frac{19}{3} + \frac{9}{2} = \frac{-38 + 27}{6} = -\frac{11}{6} \)
4. \( 0,16 - \frac{62}{75} = \frac{16}{100} - \frac{62}{75} = \frac{4}{25} - \frac{62}{75} = \frac{12 - 62}{75} = -\frac{50}{75} = -\frac{2}{3} \)
5. \( -\frac{11}{6} : \left( -\frac{2}{3} \right) = \frac{11}{6} \cdot \frac{3}{2} = \frac{11}{4} \)

Ответ: \( \frac{11}{4} \).