4) 6x² + x − 1 = 0

Question

Дискриминант: \(D=1^2-4\cdot6\cdot(-1)=25\).

\(x=\frac{-1\pm\sqrt{25}}{12}=\frac{-1\pm5}{12}\).

\(x_1=\frac{4}{12}=\frac13\), \(x_2=\frac{-6}{12}=-\frac12\).

Ответ: \(x_1=\frac13,\ x_2=-\frac12\).

Accepted Answer

Дискриминант: \(D=1^2-4\cdot6\cdot(-1)=25\).

\(x=\frac{-1\pm\sqrt{25}}{12}=\frac{-1\pm5}{12}\).

\(x_1=\frac{4}{12}=\frac13\), \(x_2=\frac{-6}{12}=-\frac12\).

Ответ: \(x_1=\frac13,\ x_2=-\frac12\).