4. Скалярное произведение векторов (координаты) 1. а(2;-1; 4), b(3; 0; -2) 2. a(-3; 5; 1), b(4; 2; -1) 3. a(0; 6; -2), b(5; -3; 1)

Question

Accepted Answer

\( \vec{a}(2;-1; 4), \vec{b}(3; 0; -2) \)
\( \vec{a} \cdot \vec{b} = 2 \cdot 3 + (-1) \cdot 0 + 4 \cdot (-2) = 6 + 0 - 8 = -2 \)
\( \vec{a}(-3; 5; 1), \vec{b}(4; 2; -1) \)
\( \vec{a} \cdot \vec{b} = (-3) \cdot 4 + 5 \cdot 2 + 1 \cdot (-1) = -12 + 10 - 1 = -3 \)
\( \vec{a}(0; 6; -2), \vec{b}(5; -3; 1) \)
\( \vec{a} \cdot \vec{b} = 0 \cdot 5 + 6 \cdot (-3) + (-2) \cdot 1 = 0 - 18 - 2 = -20 \)

Ответ: 1. -2; 2. -3; 3. -20.