Ответ:

  1. \(2\sqrt3+5\sqrt{12}-3\sqrt{27}=2\sqrt3+10\sqrt3-9\sqrt3=3\sqrt3\), поскольку \(\sqrt{12}=2\sqrt3\) и \(\sqrt{27}=3\sqrt3\).

  2. \((\sqrt{32}-\sqrt8)\sqrt2=(4\sqrt2-2\sqrt2)\sqrt2=2\sqrt2\cdot\sqrt2=4\).

  3. \((\sqrt5-2)^2=(\sqrt5)^2-2\cdot\sqrt5\cdot2+2^2=9-4\sqrt5\).

  4. \((\sqrt6+4\sqrt3)(\sqrt6-4\sqrt3)=(\sqrt6)^2-(4\sqrt3)^2=6-48=-42\).

Ответ: 1) \(3\sqrt3\); 2) 4; 3) \(9-4\sqrt5\); 4) −42.