Решение:
\[ \frac{a^2-2a}{6-3a} = \frac{a(a-2)}{3(2-a)} = \frac{a(a-2)}{-3(a-2)} = -\frac{a}{3} \]
\[ -\frac{a}{3} = -\frac{-108}{3} = \frac{108}{3} = 36 \]
Ответ: 36