Ответ:
\(\frac{15a^2+10ab}{3ab+2b^2}=\frac{5a(3a+2b)}{b(3a+2b)}=\frac{5a}{b}\).
При заданных значениях: \(\frac{5\cdot(-2)}{0.4}=-25\).
\(\frac{9b^2-4c^2}{12b^2c-8bc^2}=\frac{(3b-2c)(3b+2c)}{4bc(3b-2c)}=\frac{3b+2c}{4bc}\).
\(\frac{3\cdot\frac13+2\cdot(-6)}{4\cdot\frac13\cdot(-6)}=\frac{1-12}{-8}=\frac{11}{8}\).
\(\frac{36x^2-12xy+y^2}{y^2-36x^2}=\frac{(6x-y)^2}{(y-6x)(y+6x)}=\frac{y-6x}{y+6x}\).
\(\frac{-3-6\cdot1.2}{-3+6\cdot1.2}=\frac{-10.2}{4.2}=-\frac{17}{7}\).
\(\frac{a^8-a^6}{a^9+a^8}=\frac{a^6(a-1)(a+1)}{a^8(a+1)}=\frac{a-1}{a^2}\).
При \(a=-0.1\): \(\frac{-0.1-1}{(-0.1)^2}=\frac{-1.1}{0.01}=-110\).
Ответ: 1) \(-25\); 2) \(\frac{11}{8}\); 3) \(-\frac{17}{7}\); 4) \(-110\).
