Ответ:

Перевод задания: Приведите дроби к наименьшему общему знаменателю.

Әр тармақта бөлімдердің ЕКОЕ-сін табамыз және бөлшектерді соған келтіреміз.

  1. ЕКОЕ(2, 6, 3) = 6: \(\frac{1}{2}=\frac{3}{6}\), \(\frac{1}{6}=\frac{1}{6}\), \(\frac{2}{3}=\frac{4}{6}\).
  2. ЕКОЕ(4, 7, 28) = 28: \(\frac{1}{4}=\frac{7}{28}\), \(\frac{5}{7}=\frac{20}{28}\), \(\frac{9}{28}=\frac{9}{28}\).
  3. ЕКОЕ(5, 20, 10) = 20: \(\frac{1}{5}=\frac{4}{20}\), \(\frac{11}{20}=\frac{11}{20}\), \(\frac{3}{10}=\frac{6}{20}\).
  4. ЕКОЕ(4, 8, 16) = 16: \(\frac{3}{4}=\frac{12}{16}\), \(\frac{7}{8}=\frac{14}{16}\), \(\frac{3}{16}=\frac{3}{16}\).
  5. ЕКОЕ(3, 15, 5) = 15: \(\frac{2}{3}=\frac{10}{15}\), \(\frac{2}{15}=\frac{2}{15}\), \(\frac{4}{5}=\frac{12}{15}\).
  6. ЕКОЕ(2, 9, 6) = 18: \(\frac{1}{2}=\frac{9}{18}\), \(\frac{1}{9}=\frac{2}{18}\), \(\frac{5}{6}=\frac{15}{18}\).

Перевод решения: В каждом пункте находим наименьшее общее кратное знаменателей и приводим к нему дроби.

  1. НОК(2, 6, 3) = 6: \(\frac{1}{2}=\frac{3}{6}\), \(\frac{1}{6}=\frac{1}{6}\), \(\frac{2}{3}=\frac{4}{6}\).
  2. НОК(4, 7, 28) = 28: \(\frac{1}{4}=\frac{7}{28}\), \(\frac{5}{7}=\frac{20}{28}\), \(\frac{9}{28}=\frac{9}{28}\).
  3. НОК(5, 20, 10) = 20: \(\frac{1}{5}=\frac{4}{20}\), \(\frac{11}{20}=\frac{11}{20}\), \(\frac{3}{10}=\frac{6}{20}\).
  4. НОК(4, 8, 16) = 16: \(\frac{3}{4}=\frac{12}{16}\), \(\frac{7}{8}=\frac{14}{16}\), \(\frac{3}{16}=\frac{3}{16}\).
  5. НОК(3, 15, 5) = 15: \(\frac{2}{3}=\frac{10}{15}\), \(\frac{2}{15}=\frac{2}{15}\), \(\frac{4}{5}=\frac{12}{15}\).
  6. НОК(2, 9, 6) = 18: \(\frac{1}{2}=\frac{9}{18}\), \(\frac{1}{9}=\frac{2}{18}\), \(\frac{5}{6}=\frac{15}{18}\).