Вопрос:

47. Вычислите: \(2\frac{1}{2}+\frac{9}{16}\cdot1\frac{5}{27}-3\frac{3}{7}:\frac{27}{28}\).

Ответ:

\(2\frac{1}{2}=\frac52\), \(1\frac{5}{27}=\frac{32}{27}\), \(3\frac{3}{7}=\frac{24}{7}\).

\(\frac{9}{16}\cdot\frac{32}{27}=\frac23\), \(\frac{24}{7}:\frac{27}{28}=\frac{24}{7}\cdot\frac{28}{27}=\frac{32}{9}\).

\(\frac52+\frac23-\frac{32}{9}=\frac{45+12-64}{18}=-\frac{7}{18}\).

Ответ: \(-\frac{7}{18}\).