Дано: уравнение \( \frac{5}{7}y + \frac{2}{3}y - 4 = \frac{1}{7} \).
Найти: значение \( y \).
Решение:
\[ \frac{5}{7}y + \frac{2}{3}y = \frac{1}{7} + 4 \]
\[ \frac{1}{7} + \frac{28}{7} = \frac{1+28}{7} = \frac{29}{7} \]
\[ \frac{5 \cdot 3}{7 \cdot 3}y + \frac{2 \cdot 7}{3 \cdot 7}y = \frac{15}{21}y + \frac{14}{21}y = \frac{15+14}{21}y = \frac{29}{21}y \]
\[ \frac{29}{21}y = \frac{29}{7} \]
\[ y = \frac{29}{7} \cdot \frac{21}{29} \]
\[ y = \frac{1}{1} \cdot \frac{3}{1} = 3 \]
Ответ: \( y = 3 \).