5) Analysis:
In the given figure, we have a triangle LNP with a point M on the side LP and a segment MN drawn from M to vertex N.
The markings indicate:
- Segment LM is equal to segment MP (indicated by single tick marks). This means that point M is the midpoint of side LP.
- Segment LN is equal to segment NP (indicated by double tick marks). This means that triangle LNP is an isosceles triangle with the base LP.
- The angle at vertex N is marked with a right angle symbol, but this symbol is at the vertex N, not indicating that MN is perpendicular to LP or that LN is perpendicular to NP. The arc at N indicates an angle, and the perpendicular symbol at M is not present. However, if we assume the right angle symbol is at N (angle LNP is 90 degrees), then triangle LNP is a right-angled isosceles triangle.
Let's re-examine the image. The right angle symbol is clearly at vertex N. The arc at N is indicating the angle. The markings on LN and NP indicate they are equal. Therefore, triangle LNP is an isosceles right-angled triangle.
The segment MN connects the midpoint M of the hypotenuse LP to the vertex N (the right angle).
Conclusions:
- Triangle LNP is an isosceles right-angled triangle (since LN = NP and angle LNP = 90 degrees).
- Segment MN is the median to the hypotenuse of the right-angled triangle LNP.
In a right-angled triangle, the median to the hypotenuse is half the length of the hypotenuse. Therefore, MN = LM = MP.
This also implies that triangle LMN and triangle PMN are isosceles triangles.
Conclusion: Triangle LNP is an isosceles right-angled triangle. MN is the median to the hypotenuse, and therefore MN = LM = MP.